W^3+2w^2-24w=0

Solution for W^3+2w^2-24w=0 equation:

^3+2W^2-24W=0

We add all the numbers together, and all the variables

2W^2-24W=0

a = 2; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·2·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*2}=\frac{0}{4}
=0
$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*2}=\frac{48}{4}
=12
$